"""
Count to 20 in one second steps
"""
from time import sleep
for i in range(1,21):
print(str(i))
sleep(1)
Next I created a python module to spawn off a process to call the counter and print the output.
"""
Call the slow-running counter and print the results.
"""
import pexpect
output = pexpect.run('python count-slow.py')
print(output)
The problem of course is that the run command blocks until all the output is produced. The solution allowing you to see the output as it appears is to use the pexpect.spawn() function. This function to creates a sub-process object from which you can read one line at a time. Pyexpect.readline() will block until it receives a line. An empty string indicates the process has completed.
"""
Call the slow-running counter and print the results.
"""
import pexpect
child = pexpect.spawn('python count-slow.py')
next_line = child.readline()
while next_line != '':
print(next_line.strip())
next_line = child.readline()
